√ Java Output Formatting- hacker rank solution 2020

Java Output Formatting- hacker rank solution 2020

Tuesday, 1 September 2020

Java Output Formatting

To get you started, a portion of the solution is provided for you in the editor; you must format and print the input to complete the solution.

Input Format

Every line of input will contain a String followed by an integer.

Each String will have a maximum of alphabetic characters, and each integer will be in the inclusive range from to.

Output Format

In each line of output there should be two columns:

The first column contains the String and is left-justified using exactly characters.

The second column contains the integer, expressed in exactly digits; if the original input has less than three digits, you must pad your output's leading digits with zeroes.

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc=new Scanner(System.in);
            System.out.println("================================");
            for(int i=0;i<3;i++){
                String s1=sc.next();
                int x=sc.nextInt();
                System.out.printf("%-15s%03d%n", s1, x);
            }
            System.out.println("================================");

    }
}

In java we used ("%-15s%03d%n", s1, x) % as a formatter. where '-' : minus sign used for left indentation of the string. 15s : is denotes the string's minimum field width 15. '0' : denotes the pads the extra 0s in the integer. 3d : here 3 denotes integer's minimum field width 3. %n : prints the new line.

I Hope, this helps!